x^2-8x+40=0

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Solution for x^2-8x+40=0 equation:


Simplifying
x2 + -8x + 40 = 0

Reorder the terms:
40 + -8x + x2 = 0

Solving
40 + -8x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -8x + -40 + x2 = 0 + -40

Reorder the terms:
40 + -40 + -8x + x2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -8x + x2 = 0 + -40
-8x + x2 = 0 + -40

Combine like terms: 0 + -40 = -40
-8x + x2 = -40

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -40 + 16

Reorder the terms:
16 + -8x + x2 = -40 + 16

Combine like terms: -40 + 16 = -24
16 + -8x + x2 = -24

Factor a perfect square on the left side:
(x + -4)(x + -4) = -24

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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